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Q.
Out of the following which one is not a possible energy for a photon to be emitted by hydrogen atom according to Bohr’s atomic model?
AIPMTAIPMT 2011Atoms
Solution:
The energy of $n ^{\text {th }}$ orbit of hydrogen atom is given by
$E_{n}=-\frac{13,6}{n^{2}}\, eV$
Therefore, $E _{1}=-13.6\, eV$
$E _{2}=-\frac{13.6}{2^{2}}=-3.4\, eV$
$E _{3}=-\frac{-13.6}{3^{2}}=-1.5\, eV$
$E _{4}=-\frac{13.6}{4^{2}}=-0.85\, eV$
So, $E _{3}- E _{2}=-1.5-(-3.4)=1.9 \, eV$
and $E _{4}- E _{3}=-0.85-(-1.5)=.0 .65\, eV$
Hence correct answer is $11.1 \, eV$