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Q. Osmotic pressure of a solution is $0.0821 \,atm$ at a temperature of $300 \,K$. The concentration in moles/litre will be

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Solution:

$\pi = CRT $
$C =\frac{\pi}{R T}=\frac{0.0821}{0.0821 \times 300} $
$=0.3 \times 10^{-2} mol \,L ^{-1}$