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Q. Osmotic pressure of a solution is $0.0821$ atm at a temperature of $300\,K$. The concentration in .mole per litre will be:

Haryana PMTHaryana PMT 2005

Solution:

$V=n.RT $ or $ \frac{n}{V}=\frac{\pi }{RT}$
$=\frac{0.0821}{300\times 0.0821} $
$ =0.3\times 10^{-2} $ mole/litre