Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Osmotic pressure of 30% solution of glucose is 1.20 atm and that of 3.42% solution of cane sugar is 2.5 atm. The osmotic pressure of the mixture containing equal volumes of the two solutions will be

Solutions

Solution:

$\pi_{f}\,V_{f}=\pi_{1}\,V_{1}+\pi_{2}\,V_{2}$
$\pi_{f} =\frac{1.2V+2.5V}{2V}$
$=\frac{3.7V}{2V}$
$\pi_{f}=1.85$ atm