Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Optical activity of an enantiomeric mixture is $+12.6^{\circ}$ and the specific rotation of $(+)$ isomer is $+30^{\circ}$. The optical purity is ______$\%$

JEE MainJEE Main 2022General Principles and Processes of Isolation of Elements

Solution:

$\%$ optical purity
$=\frac{\text { observed rotation of mixture } \times 100}{\text { rotation of pure enantiomer }} $
$=\frac{+12.6^{\circ}}{+30^{\circ}} \times 100=42$