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Q. One stone is dropped from a tower from rest and simultaneously another stone is projected vertically upwards from the tower with some initial velocity. The graph of the distance(s) between the two stones varies with time $(t)$ as (before either stone hits the ground)

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

$s_{1}(t)=\frac{1}{2} g t^{2}$ (downwards) and
$s_{2}(t)=u t-\frac{1}{2} g t^{2}$ (upwards)
Solution
$\therefore $ Distance between the two stones will be
$s=s_{1}(t)+s_{2}(t)=u t$
Therefore, $s-t$ graph will be a straight line passing through origin.