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  4. One requires 0.01 mole of Na2CO3. Mass of Na2CO3.10 H2O to be taken is

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Q. One requires 0.01 mole of $Na_2CO_3$. Mass of $Na_2CO_3.10 H_2O$ to be taken is

Some Basic Concepts of Chemistry

Solution:

$0.01$ mol of $Na_{2}CO_{3} \equiv 0.01$ mol of $Na_{2}CO_{3}\cdot10H_{2}O$
Molar mass of $Na_{2}CO_{3}\cdot10H_{2}O=46+12+48+180=286\,g\,mol^{-1}$
Mass of $0.01$ mol of $Na_{2}CO_{3}\cdot10\,H_{2}O$
$=2.86\,g$