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Q. One mole of non-volatile solute is dissolved in two moles of water. The vapour pressure of the solution relative to that of water is

Solutions

Solution:

$\frac{P^{o}-P_{S}}{P^{o}}=\frac{1}{1+2}=\frac{1}{3}$
$\therefore 1-\frac{P_{S}}{P^{o}}=\frac{1}{3}$
Thus $\frac{P_{s}}{P^{o}}=1-\frac{1}{3}=\frac{2}{3}$