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Q. One mole of liquid $CCl _{4}$ at $298 K$ has an entropy of $214\, J / K$. What is the entropy of one mole of $CCl _{4}$ vapours in equilibrium with the liquid at this temperature, if heat of vapourization of $CCl _{4}$ is $43.0\, kJ / mol ?$

Thermodynamics

Solution:

$CCl _{4(l)} \rightarrow CCl _{4(g)} ; \Delta H=43.0 kJ =43 \times 10^{3} J$

$\Delta S=\frac{\Delta H_{\text {vap }}}{T}=\frac{43 \times 10^{3}}{298}=144.3 J$

We know $\Delta S=S_{\text {vap }}-S_{\text {liq }}$

$ \Rightarrow 144.3=S_{\text {vap }}-214$

$S_{\text {vap }}=144.3+214=358.3 \,J\, K ^{-1} mol ^{-1}$