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Q. One mole of ice is converted into water at 273 K. The entropies of $H_2O(s) \, and \,H_2O(l)$ are 38.20 and 60.01 $J mol^{-1} K^{-1}$ respectively. The enthalpy change for the conversion is

Thermodynamics

Solution:

$\Delta$H = T$\Delta$S = 273$ \times$ (60 01 - 38-20) = 5954-13 J $mol^{-1}$