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  4. One mole of ethanol is treated with one mole of ethanoic acid at 25° C. Half of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be a) 1 b) 2 c) 3 d) 4

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Q. One mole of ethanol is treated with one mole of ethanoic acid at $25^{\circ} C$. Half of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be
a) 1
b) 2
c) 3
d) 4

Equilibrium

Solution:

image
$K=\frac{\left[ CH _3 COOC _2 H _5\right]\left[ H _2 O \right]}{\left[ C _2 H _5 OH \right]\left[ CH _3 COOH \right]}=\frac{\frac{1}{2} \times \frac{1}{2}}{\frac{1}{2} \times \frac{1}{2}}=1$