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  4. One mole of ethanol is produced reacting graphite, H2 and O2 together. The standard enthalpy of formation is - 277.7 kJ mol-1. Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved

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Q. One mole of ethanol is produced reacting graphite, $H_2$ and $O_2$ together. The standard enthalpy of formation is $- 277.7 \, kJ \, mol^{-1}$. Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved

KEAMKEAM 2018Thermodynamics

Solution:

The related equation for the formation of ethanol is.

2 C(graphite)$+3 H _{2}(g)+\frac{1}{2} O _{2}(g) \longrightarrow C _{2} H _{5} OH (l)$

$\Delta H_{f}=-277.7\, kJ / mol$

When 2 moles of graphite is involved the standard enthalpy of reaction is $-277.7\, kJ / mol$ $\therefore $ When 4 moles of graphite is involved, standard enthalpy of reaction is $2 \times(-277.7\, kJ / mol )$

$=(-) 555.4\, kJ / mol$