1. Tardigrade
  2. Question
  3. Chemistry
  4. One mole of an ideal diatomic gas ( C v =5 cal ) was transformed from initial 25° C and 1 L to the state when temperature is 100° C and volume 10 L. Then for this process ( R =2 calories / mol / K ) (take calories as unit of energy and kelvin for temp)

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Q. One mole of an ideal diatomic gas $\left( C _{ v }=5 cal \right)$ was transformed from initial $25^{\circ} C$ and $1\, L$ to the state when temperature is $100^{\circ} C$ and volume $10 \,L$. Then for this process $( R =2$ calories $/ mol / K )$ (take calories as unit of energy and kelvin for temp)

Thermodynamics

Solution:

$\Delta S=n C_{v} \ln \left(\frac{T_{f}}{T_{i}}\right)+n R \ln \left(\frac{V_{f}}{V_{i}}\right)$
$\Delta H = nC _{p} \Delta T$
$\Delta E = nC _{v} \Delta T$
$\Delta G =\Delta H -\Delta( TS )$