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  4. One mole of a diatomic gas undergoes a thermodynamic process, whose process equation is P propto V2 . The molar specific heat of the gas is

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Q. One mole of a diatomic gas undergoes a thermodynamic process, whose process equation is $P \propto V^{2}$ . The molar specific heat of the gas is

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Given $PV^{- 2}=$ constant
Comparing with $PV^{N}=$ constant, we get
$\therefore N=-2$
$C=C_{v}+\frac{R}{1 - N}=\frac{5 R}{2}+\frac{R}{1 + 2}=\frac{5 R}{2}+\frac{R}{3}$
$=\frac{15 R + 2 R}{6}=\frac{17 R}{6}$