1. Tardigrade
  2. Question
  3. Chemistry
  4. One mole of a compound AB reacts with one mole of a compound CD according to the equation, A B(g)+CD(g) leftharpoons AD(g)+C B(g). When equilibrium had been established it was found that 3 / 4 mole each of reactants AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

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Q. One mole of a compound $AB$ reacts with one mole of a compound $CD$ according to the equation,
$A B_{(g)}+CD_{(g)} \rightleftharpoons AD_{(g)}+C B_{(g)}$. When equilibrium had been established it was found that $3 / 4$ mole each of reactants $AB$ and $CD$ had been converted to $AD$ and $CB$. There is no change in volume. The equilibrium constant for the reaction is

Equilibrium

Solution:

image

$K_{c}=\frac{[A D][C B]}{[A B][C D]}=\frac{3 / 4 \times 3 / 4}{1 / 4 \times 1 / 4}=9$