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Q. One litre of a solution contains $18.9\, g$ of $HNO_3$ and one litre of another solution contains $3.2\, g$ of $NaOH$. In what volume ratio these solution be mixed to obtain a neutral solution?

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Solution:

$eq_{HNO_3} = eq_{NaOH}$
$\frac{18.9}{63} \times 1\times V_1 = \frac{3.2}{40} \times 1 \times V_2$
$\Rightarrow \frac{V_1}{V_2} = \frac{201.6}{756} = 4 : 15$