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  4. One litre of 1 M CuSO4 solution is electrolysed. After passing 2 F of electricity, the molarity of solution will be

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Q. One litre of $1 \,M \,CuSO_4$ solution is electrolysed. After passing $2 F$ of electricity, the molarity of solution will be

Electrochemistry

Solution:

$Cu^{2+} +2e^- \rightarrow Cu$
$2\, F$ will decompose $1$ mol of $Cu^{2+}$ and will deposit
$1$ mol of copper
$1L$ of $1M \,CuSO_4$ solution contains $1$ mol of $CuSO_4$. Therefore, molarity after electrolysis $= 0$