Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. One gram of $Na_3AsO_4$ is boiled with excess of solid $KI$ in presence of strong $HCl$. The iodine evolved is absorbed in $KI$ solution and titrated against $0.2\, N$ hyposolution. Assuming the reaction to be
$AsO^{3-}_{4} + 2H^{+} + 2I^{-} \to AsO^{3-}_{3} + H_{2}O + I_{2}$, calculate the volume of thiosulphate hypo consumed. [Atomic weight of $As = 75$ ]

Redox Reactions

Solution:

image
molar mass $Na_{3}AsO_{4}$
$= 23 \times 3 + 75 + 16 \times 4$
molar mass $= 208$
$eq. of As O_{4}^{-}= \frac{1}{\left(\frac{208}{2}\right)}=\left(\frac{1}{104}\right)$
equivalent of $Na_{3}AsO_{4}=$ equivalent of$I_{2}$
$ =$ equivalent of $Na_{2} S_{2}O_{3}$
$\frac{1}{104}=.2 \times V$
$\frac{1}{104 \times.2}L=V =48.1 ML $