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  4. One gram mole of a gas at NTP occupies 22.4 L. This fact was derived from

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Q. One gram mole of a gas at NTP occupies $22.4\, L$. This fact was derived from

AIIMSAIIMS 1998Some Basic Concepts of Chemistry

Solution:

According to ideal gas equation, $P V=n R T$
Putting the standard conditions,
i.e. $P =1$ atm $n=1$ mole,
$R=0.0821\, L$ atm $K^{-1}$, mol $^{-1},$
$T=273\, K$
$V=\frac{n R T}{P}=\frac{1 \text { mole } \times 0.0821 L\,atm K^{-1} mol ^{-1} \times 273\, K }{1 atm }$
$V=22.4$