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  4. One goes from the centre of the earth to a distance two third the radius of the earth. The acceleration due to gravity is highest at

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Q. One goes from the centre of the earth to a distance two third the radius of the earth. The acceleration due to gravity is highest at

NTA AbhyasNTA Abhyas 2020Gravitation

Solution:

The acceleration due to gravity at a depth $d$ inside the earth is
$g'=g\left(1 - \frac{d}{R}\right)=g\left(\frac{R - d}{R}\right)=g\frac{r}{R}$
where, $R-d=r=$ distance of a place from the centre of earth, therefore, $g'\propto r$