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  4. One Faraday of electricity is passed through molten Al2O3 aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al,Cu and Na deposited at the respective cathode is

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Q. One Faraday of electricity is passed through molten $Al_2O_3$ aqueous solution of $CuSO_4$ and molten $NaCl$ taken in three different electrolytic cells connected in series. The mole ratio of $Al,Cu$ and $Na$ deposited at the respective cathode is

KEAMKEAM 2010Electrochemistry

Solution:

$Al^{3+} + 3e^- \rightarrow Al$
$Cu^{2+} + 2e^- \rightarrow Cu$
$Na^+ + e^- \rightarrow Na$
Hence, $1 \,F$ will deposit $1/3$ mole of $Al$, $1/2$ mol
of $Cu$ and $1$ mole of $Na$
$\therefore $ molar ratio $ = \frac{1}{3} : \frac{1}{2} : 1$
$ = 2 : 3 : 6$