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Q. One end of a string of length $1.0\, m$ is tied to a body of mass $0.5\, kg$. It is whirled in a vertical circle with angular frequency $4\, rad/s$. The tension in the string, when the body is at the lower most point of its motion, will be equal to (Take $ g=10\,m/s^{2} $ )

AMUAMU 2012Work, Energy and Power

Solution:

Tension $T=m \omega^{2} r+ m g$
$=0.5 \times(4)^{2} \times 1+0.5 \times 10$ $=13\, N$

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