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  4. One cubic centimeter iron weight 12.5 mathrmgm. Then solid piece of iron whose dimensions are 35 mathrm~cm × 25 mathrm~cm × 20 mathrm~cm will weigh

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Q. One cubic centimeter iron weight $12.5 \mathrm{gm}$. Then solid piece of iron whose dimensions are $35 \mathrm{~cm} \times 25 \mathrm{~cm} \times 20 \mathrm{~cm}$ will weigh

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Solution:

$\mathrm{Vol} =l \times b \times h$
$ =35 \times 25 \times 20$
$ =17500 \mathrm{~cm}^3$
$ 1 \mathrm{~cm}^3=12.5 \mathrm{gm}$
$\therefore 17500 \times 12.5=218.75 \mathrm{~kg}$