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Q. One car moving on a straight road covers one-third of the distance with $20\, km/h$ and the rest with $60 \,km/h$. The average speed is

Chhattisgarh PMTChhattisgarh PMT 2011

Solution:

Let total distance $=x$
Average speed $=\frac{\text { total distance }}{\text { total time }}$
$=\frac{x}{\frac{x}{3 \times 20}+\frac{2 x}{3 \times 60}}$
$=\frac{180 \times x}{5 x}=36\, km / h$