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Q. One atom of an element $x$ weigh $x = 6.643 \times 10^{-23}\, g$. Number of moles of atom in $20\, kg$ is :

Some Basic Concepts of Chemistry

Solution:

Atomic weight of an element
$x = 6.643 \times 10^{-23} \times N_{A} = 40$
no. of moles of $x = \frac{20\times1000}{40} = 500$