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Q. On the sides $AB , BC , CA$ of a $\triangle ABC , 3,4,5$ distinct points (excluding vertices $A , B , C$ ) are respectively chosen. The number of triangles that can be constructed using these chosen points as vertices are

Permutations and Combinations

Solution:

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Number of triangles $={ }^{12} C _3-\left(1+{ }^4 C _3+{ }^5 C _3\right)$
$= 220 - 15 = 205$