Q.
On the basis of the information available from the reaction.
$\frac{4}{3} Al + O _{2} \rightarrow \frac{2}{3} Al _{2} O _{3}, \Delta G =-827\, KJ\, mol ^{-1}$
of $O_2, $ the minimum EMF required to carry out the electrolysis of $Al_2O_3$ is
($F = 96500\, C\, mol^{-1})$
AIPMTAIPMT 2003Electrochemistry
Solution: