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  4. On suspending a weight M g, the length l of elastic wire having area of cross-section A, becomes double the initial length. The instantaneous stress action on the wire is

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Q. On suspending a weight $M g$, the length $l$ of elastic wire having area of cross-section $A$, becomes double the initial length. The instantaneous stress action on the wire is

Mechanical Properties of Solids

Solution:

When the length of wire becomes doubled, its area of cross-section will become half because volume of wire is constant $(V=A L)$.
So, the instantaneous stress $=\frac{\text { force }}{\text { area }}=\frac{M g}{A / 2}=\frac{2 M g}{A}$