Question

On subjecting mesityl oxide to the iodoform reaction, one of the products is the sodium salt of an organic acid. Which acid is obtained?

• A. $\left( CH _{3}\right)_{2} C = CH - CH _{2} COOH$
• B. $\left( CH _{3}\right)_{2} C = CH - CO - COOH$
• C. $\left( CH _{3}\right)_{2} C = CH - COOH$
• D. $\left( CH _{3}\right)_{2} CH - COOH$

Answer 1

Answer: (C)

Mesityl oxide undergoes iodoform reaction.
$CH _{3}- \overset{\underset{|}{CH_3}}{C} = CH - \overset{\underset{||}{O}}{C} - CH _{3} \xrightarrow{ NnOH +I_2}CH _{3}-\overset{\underset{|}{CH_3}}{C} = CH - COONa + CHI _{3}$