Question

On reaction with sodium, $1 \,mol$ of a compound $X$ gives $1\, mol$ of $H _{2}$. Which one of the following compounds might be $X$ ?

• A. $CH _{3} CH _{2} CH = CH _{2}$
• B. $CH _{3} COOCH _{2} CH _{3}$
• C. $CH _{3} CH _{2} CH _{2} OH$
• D. $CH _{2}\left( OH ^{2}\right) CH _{2} CH _{2} CH _{2} OH$

Answer 1

Answer: (D)

Since $1$ mole of compound $X$ reacts with $Na$ to evolve $1$ mole of $H_{2}$ gas,
therefore the compound should have $2$ active hydrogen atoms per mole which is possible only in option $d$.
$CH _{2} OHCH _{2} CH _{2} CH _{2} OH +2 Na \rightarrow NaOCH _{2} CH _{2} CH _{2} CH _{2} ONa +2 H$