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Q. On passing a current through a $ \text{KCl} $ solution, 19.5 g of potassium is deposited. If the same quantity of electricity is passed through a solution of aluminium chloride, the amount of aluminium deposited is :

EAMCETEAMCET 1997

Solution:

According to Faradays second law of electrolysis, the amount of different substances deposited by the passage of same quantity of electricity are proportional to their chemical equivalent weights. $ W\propto E $ $ \frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}} $ $ {{W}_{KCl}}=19.5g;{{E}_{{{K}^{+}}}}=39 $ $ {{W}_{AlC{{l}_{3}}}}=?;{{E}_{A{{l}^{3+}}}}=\frac{27}{3}=9 $ then , $ \frac{19.5}{x}=\frac{39}{9} $ $ x=\frac{19.5\times 9}{39}=4.5\,g $ So, 4.5 g of aluminium is deposited.