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Chemistry
On oxidation of S2O32 - by MnO4- in neutral aqueous medium, the oxidation number of S would change from:
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Q. On oxidation of $S_{2}O_{3}^{2 -}$ by $MnO_{4}^{-}$ in neutral aqueous medium, the oxidation number of S would change from:
NTA Abhyas
NTA Abhyas 2022
A
+6 to -2
B
-2 to +2
C
+2 to +6
D
+4 to +6
Solution:
In neutral aqueous medium, thiosulphate is oxidised almost quantitatively to sulphate: $8 \, \text{Mn} \text{O}_{4}^{-} + 3 \, \text{S}_{\text{2}} \text{O}_{3}^{2 -} + \text{H}_{\text{2}} \text{O} \rightarrow 8 \, \text{MnO}_{2} + 6 \, \text{SO}_{4}^{2 -} + 2 \text{OH}^{-}$
In $S_{2}O_{3}^{2 -}$ ,average oxidation number of Sulphur = $\frac{+ 6 - 2}{2}=+2$