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Q. On electrolysis of dil.sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be:

NEETNEET 2020Electrochemistry

Solution:

Dissociation of sulfuric acid,
$H _{2} SO _{4} \rightarrow 2 H ^{+}( aq )+ SO _{4}^{-2}( aq )$
Disssociation of water,
$H _{2} O \rightarrow H ^{+}( aq )+ OH ^{-}( aq )$
At Anode : $4 OH ^{-} \rightarrow 2 H _{2} O ^{+}( l )+ O _{2}( g )+4 e ^{-}$
At Cathode: $2 H ^{+}( aq )+2 e ^{-} \rightarrow H _{2}( g )$