Q. On decomposition of $NH _{4} HS$, the following equilibrium is established. $NH _{4} HS ( s ) \rightleftharpoons NH _{3}( g )+ H _{2} S ( g ) .$ If the total pressure is $P$ atm, then the equilibrium constant $K _{ p }$ will be equal to $\frac{ P ^{2}}{ x }$ atm $^{2}$ where $x$ is __
Equilibrium
Solution: