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Q.
On comparison of S and $ S ^{2-}$ the $ {{S}^{2-}} $ has
Rajasthan PETRajasthan PET 2007
Solution:
$ {{S}^{2-}} $ forms on adding two electron in sulphur atom, so that the effective nuclear charge decreases and the electron orbital increases. Therefore, the size and radius of $ {{S}^{2-}} $ is greater than the sulphur atom.