Thank you for reporting, we will resolve it shortly
Q.
On carrying out electrolysis of acidified water,the volume of hydrogen liberated at S.T.P. is $22.4 \,L$. The volume of oxygen liberated under similar conditions is
Electrochemistry
Solution:
$2H_2O \rightarrow 2H_2 +O_2$, the volume of $O_2$ is half of that of $H_2$ i.e., $11.2$