1. Tardigrade
  2. Question
  3. Physics
  4. On applying the load, the increment in length of a wire is 1 mm. On applying the same load on another wire of same length and material, but having half the radius, the increment will be:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. On applying the load, the increment in length of a wire is $1\, mm$. On applying the same load on another wire of same length and material, but having half the radius, the increment will be:

Solution:

$\Delta l =\frac{F L}{A \gamma}=\frac{F L}{\pi r^{2} \gamma}$
$\Delta l =\frac{1}{r^{2}}$
$\Delta l_{2}=\frac{1\, m m}{\left(\frac{1}{2}\right)^{2}}=4 \,m m$