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  4. On adding excess of AgNO3 solution into 0.01 mole complex compound PtBr4 . xNH3,0.03 moles yellow precipitate was obtained, then value of ‘ x ’ is

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Q. On adding excess of $AgNO_{3}$ solution into 0.01 mole complex compound $PtBr_{4}$ . $xNH_{3},0.03$ moles yellow precipitate was obtained, then value of ‘ $x$ ’ is

NTA AbhyasNTA Abhyas 2022

Solution:

$PtBr_{4}.xNH_{3} \\ 0.01mole+AgNO_{3}Solution \\ Excess \rightarrow AgBr\downarrow \\ 0.03moles$
As 3 AgBr molecules are formed it means $3Br^{-}$ are outside the coordination sphere and only one is inside so the value of $x=5$
i.e., complex is $\left[\right.PtBrN H_{3} \left._{5}\right]Br_{3}$