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Q. On account of the earth rotating about its axis

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

$\left(\right.1\left.\right)$ as distance of surface is maximum from axis at equator, hence $v$ is maximum as $v=\omega \times r$
$\left(\right.2\left.\right)$ angular velocity is same everywhere
$\left(\right.3\left.\right)$ as distance of surface is maximum from axis at equator, hence $v$ is maximum as $v=\omega \times r$
$\left(\right.4\left.\right)$ as distance of surface is maximum from axis at equator, hence $v$ is maximum as $v=\omega \times r$