Question

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39$^{\circ}$W and 239$^{\circ}$W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39$^{\circ}$C on the Celsius scale?

• A. 78$^{\circ}$W
• B. 117$^{\circ}$W
• C. 200$^{\circ}$W
• D. 139$^{\circ}$W

Answer 1

Answer: (B)

In general, whenever we are to go from any known scale to any unknown scale, then we follow the equation $\frac{(Temperature \: on\: known\: scale)-(LFP \:for \: known\: scale)}{(UFP - LFP)_{known}}$
= $\frac{(Temperatureon\: unknown \: scale)- (LFP\: for\: unknown\: scale)}{(UFP - LFP)_{unknown}}$
or $\frac{39-0}{100-0}=\frac{t - 39}{239 - 39}$
or $t = 117^{\circ}W$
Note : LFP - Lower fixed point
UFP - Upper fixed point