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Q. Number of ways in which the letters A A B B C C can be arranged is also equal to

Permutations and Combinations

Solution:

Actual answer is equal to $\frac{6 !}{2 ! 2 ! 2 !}=90 \quad$
(A)$ 72$ ;
(B) $\frac{6 ! 3 !}{2 ! 2 ! 2 ! 3 !}$;
(C) ${ }^{10} C _2 \cdot 2 !=90$;
(D) ${ }^6 C _4 \cdot 3 !=90$