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  4. Number of ways in which 3 boys and 3 girls (all are different heights) can be arranged in a line so that boys as well as girl among themselves are in decreasing order of their height (from left)

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Q. Number of ways in which $3$ boys and $3$ girls (all are different heights) can be arranged in a line so that boys as well as girl among themselves are in decreasing order of their height (from left)

Solution:

Since order of the boys and girls are to be maintained in any of the different arrangements
$\therefore $ Required number $=\frac{6 !}{3 ! \times 3 !}=20$