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Q. Number of unpaired electrons in $ {{O}_{2}} $ molecule is

Rajasthan PMTRajasthan PMT 2007Chemical Bonding and Molecular Structure

Solution:

$O _{2}=8+8 =16$
$=\sigma 1 s^{2}, \overset{*}{\sigma} 1 s^{2}, \sigma 2 s^{2}, \overset{*}{\sigma} 2 s^{2}, \sigma 2 p_{z}^{2} $
$ \pi 2 p_{y}^{2}, \pi 2 p_{x}^{2}, \overset{*}{\pi} 2 p_{y}^{1} \overset{*}{\pi} 2 p_{x}^{1} $
$\therefore $ Number of unpaired electrons $=2$