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Q. Number of solutions of the equation $2 \sin (\{x\})=1$ in $x \in[0,2 \pi]$ is equal to
[Note: $\{k\}$ denotes fractional part of $k$.]

Relations and Functions - Part 2

Solution:

$2 \sin \{x\}=1 $
$\sin \{x\}=1 / 2$
$\{x\}=\pi / 6 \text { is the only value }$
$x=\frac{\pi}{6}, \frac{\pi}{6}+1, \frac{\pi}{6}+2, \frac{\pi}{6}+3,4+\frac{\pi}{6}, 5+\frac{\pi}{6} \Rightarrow 6$