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Q.
Number of sigma bonds in P4O10 is
NTA AbhyasNTA Abhyas 2022Chemical Bonding and Molecular Structure
Solution:
In $P_{4}O_{10}$ each phosphorus atom is surrounded by four oxygen atoms. With one oxygen atom phosphorus forms a double bond and with the other three oxygen atoms, it forms a single bond.
Thus, the total number of sigma bonds for each phosphorus atom is three for the three P−OP−O single bonds and one for the one P=OP=O double bond, so a total of four sigma bonds. There are four phosphorus atoms present in $P_{4}O_{10}$ .
So, the total number of sigma bonds present in the compound is
$4\times 4=16$ and the total number of $\pi $ bonds are $4\times 1=4$ .
Hence, $P_{4}O_{10}$ contains $16$ sigma bonds.
