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Chemistry
Number of protons, neutrons and electrons in the element 89X231 is
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Q. Number of protons, neutrons and electrons in the element $_{89}X^{231}$ is
Structure of Atom
A
89, 89, 242
12%
B
89, 142, 89
66%
C
89, 71, 89
9%
D
89, 231, 89
12%
Solution:
Number of p = number of $e^- = 89$ and neutrons 231 - 89 = 142.