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  4. Number of primary alcohols of the formula. C5H12O are:

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Q. Number of primary alcohols of the formula. $ {{C}_{5}}{{H}_{12}}O $ are:

BHUBHU 2006

Solution:

Four primary alcohols of the formula
$ {{C}_{2}}{{H}_{12}}O $ are possible.
$ C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH, $
$ CH{_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}OH $
$ C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}-C{{H}_{2}}OH, $
$ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}OH $