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  4. Number of divisiors of the form (4n+2),n ge 0 of the integer 240 is

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Q. Number of divisiors of the form $ (4n+2),n\ge 0 $ of the integer $240$ is

Bihar CECEBihar CECE 2007

Solution:

$\because 240=2^{4} .3 .5$
$\therefore $Total number of divisors $=(4+1)(2)(2)=20$
Out of these $2,6,10$ and $30$ are of the form $4 n+2$.