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  4. Number of all 3 digit numbers containing atleast one odd and atleast one even digit is

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Q. Number of all 3 digit numbers containing atleast one odd and atleast one even digit is

Permutations and Combinations

Solution:

Required number = Total - [all odd + all even]
$ = 900 - [5 · 5 · 5 + 4 · 5 · 5 ] = 900 - (125 + 100) = 900 - 225 = 675$