Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Number of 4-digit numbers that are less than or equal to 2800 and either divisible by 3 or by 11 , is equal to
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Number of 4-digit numbers that are less than or equal to 2800 and either divisible by 3 or by 11 , is equal to
JEE Main
JEE Main 2023
Permutations and Combinations
A
B
C
D
Solution:
$1000-2799$
Divisible by 3
$1002+(n-1) 3=2799$
$n=600$
Divisible by 11
$ 1-2799 \rightarrow\left[\frac{2799}{11}\right]=[254]=254$
$ 1-999=\left[\frac{999}{11}\right]=90 $
$ 1000-2799=254-90=164$
Divisible by 33
$ 1-2799 \rightarrow\left[\frac{2799}{33}\right]=84 $
$ 1-999 \rightarrow\left[\frac{999}{33}\right]=30$
$ 1000-2799 \rightarrow 54$
$ \therefore n (3)+ n (11)- n (33) $
$ 600+164-54=710$